6[1-(4x-3)]=8(4-2x)

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Solution for 6[1-(4x-3)]=8(4-2x) equation:


Simplifying
6[1 + -1(4x + -3)] = 8(4 + -2x)

Reorder the terms:
6[1 + -1(-3 + 4x)] = 8(4 + -2x)
6[1 + (-3 * -1 + 4x * -1)] = 8(4 + -2x)
6[1 + (3 + -4x)] = 8(4 + -2x)

Combine like terms: 1 + 3 = 4
6[4 + -4x] = 8(4 + -2x)
[4 * 6 + -4x * 6] = 8(4 + -2x)
[24 + -24x] = 8(4 + -2x)
24 + -24x = (4 * 8 + -2x * 8)
24 + -24x = (32 + -16x)

Solving
24 + -24x = 32 + -16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16x' to each side of the equation.
24 + -24x + 16x = 32 + -16x + 16x

Combine like terms: -24x + 16x = -8x
24 + -8x = 32 + -16x + 16x

Combine like terms: -16x + 16x = 0
24 + -8x = 32 + 0
24 + -8x = 32

Add '-24' to each side of the equation.
24 + -24 + -8x = 32 + -24

Combine like terms: 24 + -24 = 0
0 + -8x = 32 + -24
-8x = 32 + -24

Combine like terms: 32 + -24 = 8
-8x = 8

Divide each side by '-8'.
x = -1

Simplifying
x = -1

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